Question

What mass of carbon dioxide is produced from the complete combustion of 2.10×10−3 g of methane? Express your answer with the appropriate units.

What mass of water is produced from the complete combustion of 2.10×10−3 g of methane? Express your answer with the appropriate units.

What mass of oxygen is needed for the complete combustion of 2.10×10−3 g of methane? Express your answer with the appropriate units.

Answer 1

combution reaction is

CH₄ + 2O₂    CO₂  + 2H₂O

molar mass of methane = 16.04 gm/mole then 2.10 10^-3 gm of methane = 2.10 10^-3 / 16.04 = 0.000131 mole

According to reaction 1 mole methane produce 1 mole carbon dioxide then 0.000131 mole methane produce 0.000131 mole carbon dioxide

molar mass of carbon dioxide = 44.01 gm/mole then 0.000131 mole of carbon dioxide = 0.000131 44.01 =

5.76 10^-3 gm of CO₂

According to reaction 1 mole methane produce 2 mole water then 0.000131 mole methane produce 0.000131 2 = 0.000262 mole water

molar mass of water = 18.01528 gm/mole then 0.000131 mole of carbon dioxide = 0.000262 18.01528 =

4.72 10^-3 gm of H₂O

According to reaction to react with 1 mole methane require 2 mole oxygen then 0.000131 mole methane require 0.000131 2 = 0.000262 mole oxygen

molar mass of oxygen = 33.9988 gm/mole then 0.000262 mole of oxygen = 0.000262 31.9988 =

8.38 10^-3 gm of O₂