Question

A. What mass of carbon dioxide is produced from the complete combustion of 3.30×10−3 g of methane?

B. What mass of water is produced from the complete combustion of 3.30×10−3 g of methane?

C. What mass of oxygen is needed for the complete combustion of 3.30×10−3 g of methane?

Answer 1

Combution reaction of methane

CH₄ + 2O₂    CO₂ + 2H₂O

A) molar mass of CH₄ = 16.04gm/mol that mean 1 mole of CH₄ = 16.04gm              

molar mass of CO₂ = 44.01gm/mol that mean 1 mole of CO₂ = 44.01gm

According to reaction 1 mole of methane produce 1 mole of carbon dioxide that mean 16.04 gm of methane produce 44.01 gm of carbon dioxide then 3.30×10^-3 g of methane produce 3.30×10^-3 44.01/16.04 = 9.054×10^-3

gm of carbon dioxide.

3.30×10^-3 g of methane produce 9.054×10^-3 gm of carbon dioxide.

B. )

molar mass of CH₄ = 16.04gm/mol that mean 1 mole of CH₄ = 16.04gm              

molar mass of H₂O = 18.01528gm/mol that mean 2 mole of H₂​O  = 36.03056gm

According to reaction 1 mole of methane produce 2 mole of H₂​O that mean 16.04 gm of methane produce 36.03056 gm of H₂​O then 3.30×10^-3 g of methane produce 3.30×10^-3 36.03056/16.04 = 7.412×10^-3

gm of H₂​O .

3.30×10^-3 g of methane produce 7.412×10^-3 gm of H₂​O

C)

molar mass of CH₄ = 16.04gm/mol that mean 1 mole of CH₄ = 16.04gm              

molar mass of O₂ = 31.988gm/mol that mean 2 mole of O₂   = 63.9976gm

According to reaction 1 mole react with 2 mole of O₂  that mean 16.04 gm of methane react with 63.9976 gm of O₂  then 3.30×10^-3 g of methane react with 3.30×10^-3 63.9976/16.04 = 1.3166×10^-2

gm of O₂ .

3.30×10^-3 g of react with 1.3166×10^-2 gm of O₂  for complete combution