In: Statistics and Probability
Last year's records of auto accidents occurring on a given section of highway were classified according to whether the resulting damage was $1,000 or more and to whether a physical injury resulted from the accident. The data follows.
Under $1,000 | $1,000 or More | |
Number of Accidents | 39 | 40 |
Number Involving Injuries | 10 | 23 |
(a) Estimate the true proportion of accidents involving injuries
when the damage was $1,000 or more for similar sections of highway.
(Round your answer to three decimal places.)
Find the 95% margin of error. (Round your answer to three decimal
places.)
(b) Estimate the true difference in the proportion of accidents
involving injuries for accidents with damage under $1,000 and those
with damage of $1,000 or more. Use a 95% confidence interval. (Use
p1 − p2 where
p1 is the proportion of accidents involving
injuries with damage under $1,000 and p2 is the
proportion of accidents involving injuries with damage of $1,000 or
more. Round your answers to three decimal places.)
Given,
Under $1,000 | $1,000 or More | |
Number of Accidents | 39 | 40 |
Number Involving Injuries | 10 | 23 |
(a)
Estimate for true proprotion of accidents in involving injuries when the damage was $1,000 or more for similar sections of highway = Sample proportion of accidents in involving injuries when the damage was $1,000 or more for similar sections of highway
:
Sample proportion of accidents in involving injuries when the
damage was $1,000 or more for similar sections of highway =x:
Number of accidents Involving Injuries when the
damage was $1,000 or more for similar sections of highway/ n: Total
number of accidents when the damage was $1,000 or more for similar
sections of highway =40/23= 0.575
Estimate for true proprotion of accidents in involving injuries when the damage was $1,000 or more for similar sections of highway = 0.575
Formula for 95% Margin of error for true proportion:
Given | |
n : Sample Size | 40 |
x | 23 |
![]() |
0.575 |
Confidence Level | 95% |
![]() |
0.05 |
![]() |
0.025 |
![]() |
1.96 |
95% margin of error:
95% Margin of error for true proportion: 0.153198
(b)
Under $1,000 | $1,000 or More | |
Number of Accidents n | 39 | 40 |
Number Involving Injuries:x | 10 | 23 |
SampleProportion of accidents involving in injuries | ![]() |
![]() |
:
Sample proportion of accidents in involving injuries when the
damage was $1,000 or more for similar sections of highway
=x1: Number of accidents Involving
Injuries when the damage was $1,000 or more for similar
sections of highway/ n1: Total number of accidents when
the damage was $1,000 or more for similar sections of highway
=23/40= 0.575
:
Sample proportion of accidents in involving injuries when the
damage was under $1,000 for similar sections of highway =x:
Number of accidents Involving Injuries when the
damage was $1,000 or more for similar sections of highway/ n: Total
number of accidents when the damage was under $1,000 for similar
sections of highway =10/39= 0.2564
Estimate the true difference in the proportion of accidents
involving injuries for accidents with damage under $1,000 and those
with damage of $1,000 or more =
= 0.2564-0.575=-0.3186
Formula for confidence interval for difference of two population proportions : p1-p2
![]() |
0.2564 |
![]() |
0.575 |
Confidence Level | 95% |
![]() |
0.05 |
![]() |
0.025 |
![]() |
1.96 |
95% Confidence Interval for Difference in two Population proportions
95% confidence intervale estimate for true difference in the proportion of accidents involving injuries for accidents with damage under $1,000 and those with damage of $1,000 or more =(-0.5241,-0.1131)