Question
In: Statistics and Probability
The number of M&M's in a package normally distributed with a mean of 48 candies and...
The number of M&M's in a package normally distributed with a mean of 48 candies and a standard deviation of 3. Lets say that we get 40 packages of M&M's. What is the probability that the average number of candies in those 40 packages is between 46 and 49?
0.49999
0.9825
0.3781
0.96499
Solutions
Expert Solution
Solution :
Given that ,
mean = 
= 48
standard deviation = 
= 3
n = 40
= 48
= /
P(46< <49
) = P[(46-48) /0.474 < (
-
) / < (49-48) /0.474 )]
= P(-4.26 < Z <2.13 )
= P(Z < 2.11) - P(Z <-4.26 )
Using z table
=0.9825-0
probability=0.9825
orchestra answered 2 years agoRelated Solutions
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