In: Chemistry
For the reaction 2A+B à 3C, we know that the concentration of C increases from 1M to 1.6M in 30 seconds.
What is the average reaction rate (in mM/s) during this time interval?
Hint: 1mM=10-3M
Answer :
Given reaction ,
2A + B ---> 3 C
Average Rate of reaction = change in concentration of product / ( stoichiometric coefficient * change in time )
=( 1/ n )( d[P] / dt )
Stoichiometric coefficient (n) of product = 3
dt = change in time = 30 second
Change in concentration of product = final concentration - initial concentration = 1.6 M - 1 M = 0.6 M
Average rate of reaction = (1/3) * ( 0.6 M / 30 s)
= 0.6 / 90 = 0.0066 M/s
Average rate of reaction = 0.0066 M/s
( 1 M = 1000 mM )
So, Average Rate of Reaction = 0.0066 * 1000 mM /s
= 6.6 mM /s
Average rate of reaction = 0.0066 M/s = 6.6 mM/s