The energy of a valance electron in atomic F can be calculated by Slater's rules to...

The energy of a valance electron in atomic F can be calculated by Slater's rules to be -91.9 eV. The energy of a valence electron in F^+ can be calculated to be -104.7 eV.

a) why is the energy in the valence electron inF^+ lower than F

b)what is the predicted ionizatiob energy of F?

c) why is the inoization energy so much ;ess than the energy of the valence electron ?

Expert Solution

(a) The energy of a valance electron in atomic F can be calculated by Slater's rules to be -91.9 eV. The energy of a valence electron in F⁺ can be calculated to be -104.7 eV. The energy is in the valence electron of F⁺ lower than F because F has the number of valence electrons = 7. By removing one electron the repulsion between electrons decreases so, energy decreases as well as stability increases.

(b) The predicted ionization energy of F is 1680 kJ/mole.

(c) The ionization energy so much than the energy of the valence electron because F is most electronegative atom due to this valence electron of F is tightly bounded and it is difficult to ionize. This is the reason the ionization energy is very high.

queen_honey_blossom answered 2 years ago

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