A solution of 0.312 M KOH is used to neutralize 15.0mL of an HF solution If...

A solution of 0.312 M KOH is used to neutralize 15.0mL of an HF solution If 28.3 mL of KOH is required to reach the end point, what is the morality of HF solution.

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Expert Solution

Neutrilization reaction between KOH and HF is given below

KOH + HF H₂O + KF

calculate mole of KOH

no. of mole = Molarity volume of solution in liter

28.3 ml = 0.0283 liter

no. of mole of KOH = 0.312 0.0283 = 0.0088296 mole

According to reaction KOH and HF react wih equimolar proportion therefore to react with 0.0088296 mole of KOH require 0.0088296 mole of HF for complete neutrilization ie. end point.

Molarity = no. of mole / volume of solution in liter

15 ml = 0.015

Molarity of HF = 0.0088296 / 0.015 = 0.58864 M

Molarity of HF = 0.58864 M

queen_honey_blossom answered 2 years ago

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