In: Chemistry
A solution of 0.312 M KOH is used to neutralize 15.0mL of an HF solution If 28.3 mL of KOH is required to reach the end point, what is the morality of HF solution.
Neutrilization reaction between KOH and HF is given below
KOH + HF H2O + KF
calculate mole of KOH
no. of mole = Molarity volume of solution in liter
28.3 ml = 0.0283 liter
no. of mole of KOH = 0.312 0.0283 = 0.0088296 mole
According to reaction KOH and HF react wih equimolar proportion therefore to react with 0.0088296 mole of KOH require 0.0088296 mole of HF for complete neutrilization ie. end point.
Molarity = no. of mole / volume of solution in liter
15 ml = 0.015
Molarity of HF = 0.0088296 / 0.015 = 0.58864 M
Molarity of HF = 0.58864 M