In: Statistics and Probability
In a random sample of males, it was found that 26 write with their left hands and 214 do not. In a random sample of females, it was found that 66 write with their left hands and 436 do not. Use a 0.05 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below.
H0: null Hypothesis: P1 P2
HA: Alternative Hypothesis:P1 < P2
n1= 240
p1 = 26/240 = 0.1083
n2 = 502
p2 = 66/502= 0.1315
The test statistic is given by:
Table of Area Under Standard Normal Curve gives Z = 0.3159
So,
P - value = 0.5 - 0.3159 = 0.1841
Since P - value = 0.1841 is greater than = 0.05, the difference is not significant. Fail to reject null hypothesis.
The data do not support the claim that the rate of left handedness among males is less than that among females.
For =0.05, critical value of Z = - 1.64.
Since calculated value of Z = - 0.3159 is greater than critical value of Z = - 1.64, the difference is not significant. Fail to reject null hypothesis.
The data do not support the claim that the rate of left handedness among males is less than that among females.