Question

You survey a population of cotton rats at the UH Coastal Center for variation at a SNP locus. You find 30 individuals that are C/C, 71 are C/T and 59 are T/T. what is the frequency of the T allele in this population?

For the population in the previous question, what will the frequency of the T allele be when the population is in Hardy Weinberg equilibrium?

Answer 1

Allele frequency of T = (genotypic frequency of TT) + (1/2) (genotypic frequency of CT)

Genotypic frequency of TT = 59/160 = 0.369

Genotypic frequency of CT = 71/160 = 0.444

Allele frequency of T = 0.369 + 0.444 = 0.814

Answer is 0.813.

According to Hardy weinberg equilibrium, population is said to be in a non evolving condition if it is large in size and shows random mating and no evolutionary force like mutation, migration, natural selection and genetic drift is acting upon the population. In this case The allele frequencies and genotypic frequencies remain constant across generations in the population.

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