Question

Write C Code for the following question which has two parts:

a) Show how a typedef statement can be used to declare a new data type – to demonstrate this create a new type called Person which is the structure declared previously.

b) Write C code to declare an array of 50 pointers to Persons. Using a loop, use malloc to dynamically allocate memory for each of these structures. There is no need to put any values into the structures. Use a second loop to then deallocate each structure.

Answer 1

a)

The structure declared which is represented by typedef is provided below:

typedef struct Person;

Explanation:

• The typedef is used to define the name of the variable, structure etc.
• For the structure Person, the typedef statement is provided above.

b)

The declaration of array of 50 pointers to Person structure is as follows:

struct person *Person;

Using for loop, allocation of memory using malloc is provided below:

for(int i = 0; i < 50; i++)

{

    Person = (struct Person*)malloc(50 * sizeof(struct Person));

}

Using second for loop, deallocation of the structure is provided below:

for(int i = 0; i < 50; i++)

{

    free(Person);

}

The complete code of C programming is provided below:

Screenshot of the code:

Code To Copy:

//Include the header file.

#include <stdio.h>

#include <malloc.h>

//Define the structure Person.

struct Person{

};

//Define the main function.

int main(void) {

//Declare an pointer of structure Person.

struct person *Person;

//Allocate memory for 50 persons using malloc.

for(int i = 0; i < 50; i++)

{

    Person = (struct Person*)malloc(50 * sizeof(struct

Person));

}

//Deallocate the memory for 50 persons.

for(int i = 0; i < 50; i++)

{

    free(Person);

}

}