Question

The program will enquiry from the user a name and four decimal numbers: m, a, b and h. With this information, the program will evaluate moments of inertia (a physical property) for various 3D objects and print them.

• Use the Scanner class to accept input from the user.
• Prompt the user for her/his name (i.e. “Ferdinand”).
• Using her/his name, prompt the user for a value for mass in pounds and save it in a variable (m).
• Prompt the user for a second value for an inner radius in inches and save it in another variable (a).
• Prompt the user for a third value for an outer radius in inches and save it in another variable (b).
• Prompt the user for a fourth value for a height in inches and save it in another variable (h).

·         The program will calculate the following moments of inertia for various 3D objects and save the results in variables to be printed later from these variables:

o    Moment of Inertia of a rod with length a = ma² / 12.0

o    Moment of Inertia of a rectangular parallelepiped with sides a, b and h with axis in the plane that is parallel to h = m (4a²+b² ) / 12.0

o    Moment of Inertia of a circular cylinder with radius a and height h perpendicular to the cylindrical axis = m (h²+3a² ) / 12.0

o    Moment of Inertia of a hollowed circular cylinder with radii a and b, and height h about an axis on a diameter at one end = m (3a²+3b² +4h²) / 12.0

o    Moment of Inertia of a hollowed sphere with radii a and b about its diameter =
2 m (a⁵-b⁵)/( a³-b³) / 5.0

o    Moment of Inertia of a hollowed sphere with radii a and b about an axis tangent to its surface =
2 m (a⁵-b⁵)/( a³-b³) / 5.0 + ma²

• b² means b to the power of 2. There is no need to use an especial operation for exponentiation in the program. Remember that b² is equivalent to the multiplicationof b by itself. Similarly b⁵ is equivalent to b multiplied 4 more times by b.
• Print the results of your calculations. The output should look like the example shown below. If the output does not match, there is some problem with your code.
• Students should not use Arrays, multiple methods, any other advanced concept that was not reviewed in the class to solve this assignment. Assignments that use these concepts will only be given 10% for presentation

Example
INPUT
Hi! What is your name?: Ferdinand
Ferdinand, give me a number for the mass in pounds. We are going to call it m:10
Ferdinand, give me a number for the inner radius. We are going to call it a:1
now give me a number for the outer radiosu. We are going to call it b:2
finally, give me a number for the height. We are going to call it h:10

OUTPUT
Ferdinand, with these numbers we can obtain the following moments of inertia:
Moment of Inertia of a rod with length 1.0 is
0.8333333333333334
Moment of Inertia of a rectangular parallelepiped with sides 1.0, 2.0, and 10.0 with axis in the plane that is parallel to h is
6.666666666666667
Moment of Inertia of a circular cylinder with radius 1.0, and height 10.0 perpendicular to its cylindrical axis is
85.83333333333333
Moment of Inertia of a hollowed circular cylinder with radii 1.0 and 2.0, and length 10.0 about an axis on a diameter at one end is
345.8333333333333
Moment of Inertia of a hollowed sphere with radii 1.0 and 2.0 about its diameter is
17.714285714285715
Moment of Inertia of a hollowed sphere with radii 1.0 and 2.0 about an axis tangent to its surface is
27.714285714285715

Answer 1

Code

import java.util.Scanner;
public class Inertia {

public static void main(String[] args)
{
double m,a,b,h;
Scanner sc=new Scanner(System.in);
double MIofRod,MIOfRectangularParallelepiped,MIOfCylinder,MIOfHollowedCylinder,MIhollowedSphere,MIhollowedSphereAboutXAxis;
String name;
System.out.print("Hi! What is your name?:");
name=sc.next();
System.out.print(name+", give me a number for the mass in pounds. We are going to call it m:");
m=sc.nextDouble();
System.out.print(name+", give me a number for the inner radius. We are going to call it a:");
a=sc.nextDouble();
System.out.print("now give me a number for the outer radiosu. We are going to call it b:");
b=sc.nextDouble();
System.out.print("finally, give me a number for the height. We are going to call it h:");
h=sc.nextDouble();
  
MIofRod=(m*a*a)/12.0;
MIOfRectangularParallelepiped=m*(4*a*a+b*b ) / 12.0;
MIOfCylinder= m*(h*h+3*a*a ) / 12.0;
MIOfHollowedCylinder=m*(3*a*a+3*b*b +4*h*h) / 12.0;
MIhollowedSphere=(2*(m*((a*a*a*a*a)-(b*b*b*b*b))/((a*a*a)-(b*b*b)))/5.0);
MIhollowedSphereAboutXAxis=(2*(m*((a*a*a*a*a)-(b*b*b*b*b))/((a*a*a)-(b*b*b)))/5.0+((m)*(a*a)));
  
System.out.println(name+", with these numbers we can obtain the following moments of inertia:");
System.out.println("Moment of Inertia of a rod with length "+a+"is \n"+MIofRod);
System.out.println("Moment of Inertia of a rectangular parallelepiped with sides "+a+", "+b+" and "+h+" with axis in the plane that is parallel to h is\n"+MIOfRectangularParallelepiped);
System.out.println("Moment of Inertia of a circular cylinder with radius "+a+", and height "+h+" perpendicular to its cylindrical axis is\n"+MIOfCylinder);
System.out.println("Moment of Inertia of a hollowed circular cylinder with radii "+a+" and "+b+", and length "+h+" about an axis on a diameter at one end is\n"+MIOfHollowedCylinder);
System.out.println("Moment of Inertia of a hollowed sphere with radii "+a+" and "+b+" about its diameter is\n"+MIhollowedSphere);
System.out.println("Moment of Inertia of a hollowed sphere with radii "+a+" and "+b+" about an axis tangent to its surface is\n"+MIhollowedSphereAboutXAxis);
  
}   
  
}

output

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