Question

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Q)If your current net id is 130.55.0.0 using the default subnet mask, what would be the new subnet mask if you need 12 subnets and you need to maximize the number of valid node IP addresses?

A)255.255.240.0

B)255.255.255.240

C)255.240.0.0

D)255.255.224.0

Q)Given the following IP address from the Class B address range using the default subnet mask: 131.107.0.0. Your network plan requires no more than 32 hosts on a subnet. When you configure the IP address in Cisco IOS software, which value should you use as the subnet mask?

A. 255.255.0.0

B. 255.255.128.0

C. 255.255.255.128

D. 255.255.255.252

Q) If the following are using default subnet masks, which one(s) of the following are valid node IP addresses:

a) 220.1.1.255             b) 10.10.0.0     c) 208.5.48.0      d) 1.255.255.256

Answer 1

A)255.255.240.0

Subnet Mask   "Subnet Size"   "Host Range" Broadcast
130.55.0.0   255.255.255.0   254   "130.55.0.1 to 130.55.0.254"   130.55.0.255
130.55.1.0   255.255.255.0   254   "130.55.1.1 to 130.55.1.254"   130.55.1.255
130.55.2.0   255.255.255.0   254   "130.55.2.1 to 130.55.2.254"   130.55.2.255
130.55.3.0   255.255.255.0   254   "130.55.3.1 to 130.55.3.254"   130.55.3.255
130.55.4.0   255.255.255.0   254   "130.55.4.1 to 130.55.4.254"   130.55.4.255
130.55.5.0   255.255.255.0   254   "130.55.5.1 to 130.55.5.254"   130.55.5.255
130.55.6.0   255.255.255.0   254   "130.55.6.1 to 130.55.6.254"   130.55.6.255
130.55.7.0   255.255.255.0   254   "130.55.7.1 to 130.55.7.254"   130.55.7.255
130.55.8.0   255.255.255.0   254   "130.55.8.1 to 130.55.8.254"   130.55.8.255
130.55.9.0   255.255.255.0   254   "130.55.9.1 to 130.55.9.254"   130.55.9.255
130.55.10.0   255.255.255.0   254   "130.55.10.1 to 130.55.10.254"   130.55.10.255
130.55.11.0   255.255.255.0   254   "130.55.11.1 to 130.55.11.254"   130.55.11.255
130.55.12.0   255.255.255.0   254   "130.55.12.1 to 130.55.12.254"   130.55.12.255
130.55.13.0   255.255.255.0   254   "130.55.13.1 to 130.55.13.254"   130.55.13.255
130.55.14.0   255.255.255.0   254   "130.55.14.1 to 130.55.14.254"   130.55.14.255
130.55.15.0   255.255.255.0   254   "130.55.15.1 to 130.55.15.254"   130.55.15.255

as we can not group into 12 subnet but we need in power of 2^n so we will get 16 subnets with each 254 usable hosts in each with 255.255.240.0

Answer B
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C. 255.255.255.128

Answer C
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a) 220.1.1.255 valid ip of japan
b) 10.10.0.0 valid ip of private network
c) 208.5.48.0 valid ip of USA

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