Question

(a) What is the period?
__s

(b) What is the frequency?
__Hz

(c) What is the amplitude?
__m

(d) What is the maximum speed of the glider?
__m/s

Answer 1

Effective spring oscillating distance = x = 60 cm - 10 cm = 50 cm = 0.5 m

Thus, amplitude of spring's oscillation = A = 0.5 m

No of oscillations completed = 10 in a time 33 sec

(a)   Time period = T = time taken for 1 oscillation = 33 /10= 3.3 sec     (ans)

(b) Frequency = f = 1/T = 1/ 3.3 = 0.30 Hz          (ans)

(c) Amplitude = A = 0.5 m         (ans)

(d) maximum speed of thr glider = V_ max = W A

where W is the angular velocity = 2? / T = 2(3.14) / (3.3 )    = 1.903 rad/s

   Thus, V_max = WA = (1.903)(0.5) = 0.9515 m/s                  (ans)