27.1 g of solid ethanol (MW = 46.07 g/mol) at -135.0 °C (COLD!) is warmed up...

27.1 g of solid ethanol (MW = 46.07 g/mol) at -135.0 °C (COLD!) is warmed up to room temperature (23.0 °C). Here are some relevant physical data:

Phase Cs (J/g°C) Phase change temperature and enthalpy

Gas 1.70 J/g°C boiling pt: 78.4 °C; DH_vap: 38.6.7 kJ/mol

Liquid 2.44 J/g°C freezing pt: -114.1 °C; DH_fus: 4.9 kJ/mol

Solid 2.42 J/g°C

a) What physical state will this sample of ethanol be at 23.0 °C? _________________

b) Calculate the total energy (in kJ) required in the process described above.

Please answer Parts a-b

Expert Solution

queen_honey_blossom answered 1 year ago

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