Question

In: Statistics and Probability

A mail-order catalog firm designed a factorial experiment to test the effect of the size of...

A mail-order catalog firm designed a factorial experiment to test the effect of the size of a magazine advertisement and the advertisement design on the number of catalog requests received (data in thousands). Three advertising designs and two different-size advertisements were considered. The data obtained follow.

Size of Advertisement
Small Large
Design A 8 12
12 8
B 22 26
14 30
C 10 18
18 14

Use the ANOVA procedure for factorial designs to test for any significant effects due to type of design, size of advertisement, or interaction. Use α = 0.05.

Find the value of the test statistic for type of design. (Round your answer to two decimal places.)

Find the p-value for type of design. (Round your answer to three decimal places.)

p-value =

State your conclusion about type of design.

Because the p-value ≤ α = 0.05, type of design is not significant.Because the p-value > α = 0.05, type of design is significant.     Because the p-value > α = 0.05, type of design is not significant.Because the p-value ≤ α = 0.05, type of design is significant.

Find the value of the test statistic for size of advertisement. (Round your answer to two decimal places.)

Find the p-value for size of advertisement. (Round your answer to three decimal places.)

p-value =

State your conclusion about size of advertisement.

Because the p-value ≤ α = 0.05, size of advertisement is not significant.

Because the p-value ≤ α = 0.05, size of advertisement is significant.    

Because the p-value > α = 0.05, size of advertisement is not significant.

Because the p-value > α = 0.05, size of advertisement is significant.

Find the value of the test statistic for interaction between type of design and size of advertisement. (Round your answer to two decimal places.)

Find the p-value for interaction between type of design and size of advertisement. (Round your answer to three decimal places.)

p-value =

State your conclusion about interaction between type of design and size of advertisement.

Because the p-value > α = 0.05, interaction between type of design and size of advertisement is significant

.Because the p-value > α = 0.05, interaction between type of design and size of advertisement is not significant.     

Because the p-value ≤ α = 0.05, interaction between type of design and size of advertisement is not significant

.Because the p-value ≤ α = 0.05, interaction between type of design and size of advertisement is significant.

Solutions

Expert Solution

using excel data analysis tool for two factor anova, following o/p Is obtained :

write data>menu>data>data analysis>anova :two factor with replication>enter required labels>ok, and following o/p Is obtained,

Anova: Two-Factor With Replication
SUMMARY Small Large Total
A
Count 2 2 4
Sum 20 20 40
Average 10 10 10
Variance 8 8 5.333333
B
Count 2 2 4
Sum 36 56 92
Average 18 28 23
Variance 32 8 46.66667
C
Count 2 2 4
Sum 28 32 60
Average 14 16 15
Variance 32 8 14.66667
Total
Count 6 6
Sum 84 108
Average 14 18
Variance 27.2 72
ANOVA
Source of Variation SS df MS F P-value F crit
Sample 344 2 172 10.75 0.010386 5.143253
Columns 48 1 48 3 0.133975 5.987378
Interaction 56 2 28 1.75 0.251932 5.143253
Within 96 6 16
Total 544 11

a)

value of the test statistic for type of design=10.75

p value=0.010

Because the p-value ≤ α = 0.05, type of design is significant.

-------------------------------

value of the test statistic for size of advertisement=3.00

p-value=0.134

Because the p-value > α = 0.05, size of advertisement is not significant.

-------------------------

value of the test statistic for interaction between type of design and size of advertisement=1.75

p value=0.252

.Because the p-value > α = 0.05, interaction between type of design and size of advertisement is not significant.     


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