In: Statistics and Probability
All Time Box Office Revenues Aggregated by Months
Rank |
Month |
Gross |
Movies Tracked |
1 |
February, 2009 |
796,343,640 |
161 |
2 |
February, 2010 |
745,693,066 |
173 |
3 |
February, 2008 |
659,270,466 |
193 |
4 |
February, 2004 |
666,141,251 |
201 |
5 |
February, 2007 |
693,647,238 |
176 |
6 |
February, 2003 |
613,460,961 |
207 |
7 |
February, 2005 |
692,957,988 |
185 |
8 |
February, 2006 |
652,426,175 |
193 |
9 |
February 2002 |
529,353,345 |
98 |
1. Mean for the gross revenues.
The sample size is n=9. The provided sample data along with the data required to compute the sample mean is shown in the table below:
Gross Revenue | Gross Revenue2 | |
796343640 | 634163192968449600 | |
745693066 | 556058148680480356 | |
659270466 | 434637547339857156 | |
666141251 | 443744166283845001 | |
693647238 | 481146490785028644 | |
613460961 | 376334350671043521 | |
692957988 | 480190773133008144 | |
652426175 | 425659913825130625 | |
529353345 | 280214963862689025 | |
Sum = | 6049294130 | 4.1121495475495E+18 |
The sample mean is computed as follows:
2. Mean for the Movies tracked.
The sample size is n=9. The provided sample data along with the data required to compute the sample mean and sample variance are shown in the table below:
Movies Tracked | Movies Tracked2 | |
161 | 25921 | |
173 | 29929 | |
193 | 37249 | |
201 | 40401 | |
176 | 30976 | |
207 | 42849 | |
185 | 34225 | |
193 | 37249 | |
98 | 9604 | |
Sum = | 1587 | 288403 |
The sample mean is computed as follows:
3. The standard deviation for the movies tracked.
Also, the sample variance is
Therefore, the sample standard deviation s is
Please do upvote if you are satisfied! Let me know in the comments if anything is not clear. I will reply ASAP!