In: Statistics and Probability
Vitamin D, whether ingested as a dietary supplement or produced naturally when sunlight falls upon the skin, is essential for strong, healthy bones. The bone disease rickets was largely eliminated during the 1950s, but now there is concern that a generation of children more likely to watch TV or play computer games than spend time outdoors is at increased risk. A recent study of 2600 children randomly selected found 21% of them deficient in vitamin D. Complete parts a through c below.
a) Construct a 98% confidence interval for the true proportion of children who are deficient in vitamin D. Select the correct choice below and fill in any answer boxes within your choice.
A. (___, ___)
(Round to three decimal places as needed.)
B. The conditions of a confidence interval are not satisfied.
b) Explain carefully what the interval means.
A. We are 98% confident that the proportion of people deficient in vitamin D falls inside the confidence interval bounds.
B. We are 98% confident that the proportion of children deficient in vitamin D falls inside the confidence interval bounds.
C. We are 98% confident that the proportion of vitamin D deficiency in a randomly sampled child falls within the confidence interval bounds.
D. We are 98% confident that the proportion of children deficient in vitamin D is 0.21.
c) Explain what "98% confidence" means.
About 98% of random samples of size 2600 will produce ____ (pick: sample means, a true proportion, confidence intervals) that contain the ____ (pick: confidence interval, true proportion, number) of children that are deficient in vitamin D.
A)
sample proportion, = 0.21
sample size, n = 2600
Standard error, SE = sqrt(pcap * (1 - pcap)/n)
SE = sqrt(0.21 * (1 - 0.21)/2600) = 0.008
Given CI level is 98%, hence α = 1 - 0.98 = 0.02
α/2 = 0.02/2 = 0.01, Zc = Z(α/2) = 2.33
CI = (pcap - z*SE, pcap + z*SE)
CI = (0.21 - 2.33 * 0.008 , 0.21 + 2.33 * 0.008)
CI = (0.191 , 0.229)
B)
B. We are 98% confident that the proportion of children deficient
in vitamin D falls inside the confidence interval bounds.
c)
About 98% of random samples of size 2600 will produce a confidence
intervals that contain the true proportion of children that are
deficient in vitamin D.