In: Chemistry
1. What is the percent yield of MgO produced if 1.502 g of magnesium is ignited in air producing 1.699 g of MgO?
1)
2 Mg + O2 ---------------> 2 MgO
48 g 32 g 80 g
1.502 ??
48 g Mg ----------------> 80 g MgO
1.502 g Mg --------------> ??
theoretical yield of MgO = 1.502 x 80 / 48 = 2.503 g
percent yield = (actual / theoretical ) x 100
= 1.699 / 2.503 ) x 100
percent yield = 67.87 %