Question

(c++) error:

=================== MISMATCH FOUND ON LINE 0007: ===================                                         

ACTUAL  : 2~year                                                                                             

EXPECTED: 2~years                                                                                            

======================================================

#include <iostream>
using namespace std;

int main()
{
const int MonthDays[]= { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30 ,31 };
const string MonthName[]= {"jan","feb","mar","apr","may","jun","jul","aug","sep","oct","nov","dec"};
  
int day;
int year=0;
int index;
  
while(1)
{
cout<<"Please enter a day of the year (0 to exit): ";
cin>>day;
cout<<day<<endl;
  
if(day==0)
{
break;
}
  
index=0;
year=0;
while(day>365)
{
day=day-365;
year++;
}
  
if(year !=0)
{
cout<<year<<" year"<<endl;
}
  
index=0;
while(day>MonthDays[index])
{
day=day-MonthDays[index];
index++;
}
cout<<MonthName[index]<<" "<<day<<endl;
}
  
cout<<"Thanks for playing!";
  
return 0;
}

INSTRUCTIONS:

Given a number, calculate how many years into the future it is, and what date. Assume no leap years. For example: Please enter a day of the year (0 to exit): 1 jan 1 Please enter a day of the year (0 to exit): 365 dec 31 Please enter a day of the year (0 to exit): 366 1 year jan 1 Please enter a day of the year (0 to exit): 0 Thanks for playing!

Answer 1

I have answered this before. Your test program is expecting an output of ‘2 years’ for some input, but your program is giving ‘2 year’ (no s at the end). So I fixed your code to print years instead of year if n is not 1. Also your code had some misplaced statements. I made some rearrangements, now it runs perfectly as needed.

NOTE: Copy the entire code from below, and try running. DO NOT JUST CHANGE YEAR TO YEARS OR VICE VERSA. IT WONT WORK. Modified code is highlighted in bold text. Thanks

#include <iostream>

using namespace std;

int main()

{

    int daynum, n;

    cout << "Please enter a day of the year (0 to exit): ";

    cin >> daynum;

    while (daynum > 0) {

                //checking if daynum>365 at the beginning of loop

                if (daynum > 365) {

            n = daynum / 365;

            if(n==1){

                //printing year instead of years for n=1

                cout << n << " year" << endl;

                                               }else{

                                                               //printing years instead of year for n>1

                                                               cout << n << " years" << endl;

                                               }

            //updating daynum, so that it will be under 365

            daynum = daynum - (365 * n);

        }

        //now finding the day of year

        if (daynum >= 1 && daynum <= 31)

            cout << "jan " << daynum << endl;

        else if (daynum > 31 && daynum <= 59) {

            cout << "feb " << daynum - 31 << endl;

        }

        else if (daynum > 59 && daynum <= 90) {

            cout << "mar " << daynum - 59 << endl;

        }

        else if (daynum > 90 && daynum <= 120) {

            cout << "apr " << daynum - 90 << endl;

        }

        else if (daynum > 120 && daynum <= 151) {

            cout << "may " << daynum - 120 << endl;

        }

        else if (daynum > 151 && daynum <= 181) {

            cout << "jun " << daynum - 151 << endl;

        }

        else if (daynum > 181 && daynum <= 212) {

            cout << "jul " << daynum - 181 << endl;

        }

        else if (daynum > 212 && daynum <= 243) {

            cout << "aug " << daynum - 212 << endl;

        }

        else if (daynum > 243 && daynum <= 273) {

            cout << "sep " << daynum - 243 << endl;

        }

        else if (daynum > 273 && daynum <= 304) {

            cout << "oct " << daynum - 273 << endl;

        }

        else if (daynum > 304 && daynum <= 334) {

            cout << "nov " << daynum - 304 << endl;

        }

        else if (daynum > 334 && daynum <= 365) {

            cout << "dec " << daynum - 334 << endl;

        }

        cout << "Please enter a day of the year (0 to exit): ";

        cin >> daynum;

    }

    if (daynum == 0)

        cout << "Thanks for playing!";

    if (daynum < 0)

        cout << "Invalid input!";

    return 0;

}

//OUTPUT

Please enter a day of the year (0 to exit): 1

jan 1

Please enter a day of the year (0 to exit): 2

jan 2

Please enter a day of the year (0 to exit): 300

oct 27

Please enter a day of the year (0 to exit): 365

dec 31

Please enter a day of the year (0 to exit): 366

1 year

jan 1

Please enter a day of the year (0 to exit): 789

2 years

feb 28

Please enter a day of the year (0 to exit): 10000

27 years

may 25

Please enter a day of the year (0 to exit): 0

Thanks for playing!