Question

In: Statistics and Probability

Wind Mountain is an archaeological study area located in southwestern New Mexico. Potsherds are broken pieces...

Wind Mountain is an archaeological study area located in southwestern New Mexico. Potsherds are broken pieces of prehistoric Native American clay vessels. One type of painted ceramic vessel is called Mimbres classic black-on-white. At three different sites, the number of such sherds was counted in local dwelling excavations.

site I Site II Site III
61 26 13
34 10 31
28 55 65
18 63 22
78 15
50 19
26

Shall we reject or not reject the claim that there is no difference in population mean Mimbres classic black-on-white sherd counts for the three sites? Use a 10% level of significance.

(b) Find SSTOT, SSBET, and SSW and check that SSTOT = SSBET + SSW. (Use 3 decimal places.)

SSTOT

SSBET

SSW

Find d.f.BET, d.f.W, MSBET, and MSW. (Use 2 decimal places for MSBET, and MSW.)

dfBET

dfW

MSBET
MSW

Find the value of the sample F statistic. (Use 2 decimal places.)

What are the degrees of freedom?

( numerator)

  (denominator)
(c) Find the P-value of the sample test statistic. (Use 4 decimal places.)

(f) Make a summary table for your ANOVA test.

Source of
Variation
Sum of
Squares
Degrees of
Freedom
MS F
Ratio
P Value Test
Decision
Between groups .
Within groups
Total

Solutions

Expert Solution

A ) level of significance is 10% ( 0.10)

Hypothesis

No all means are equal

B) Enter data in excel sheet like this

Go to DATA ribbon. Choose ANOVA : One factor from data Analysis menu.

Output from Excel( ANOVA Table )

SSTOT = 726.765

SSBET = 722.4076

SSW = 6541.357

There are k = 3 treatment and N = 17 total observations therefore,

dfBET = ( k - 1 ) = ( 3 - 1) = 2

dfW = ( N - k ) = ( 17 - 3 ) = 14

MSBET = SBET / dfBET = 722.4076 / 2 = 361.2038

MSW = SW / dfW = 6541.357 / 14 = 467.2398

F = MSBET / MSW = 0.770359

The degree of freedom for F statistics is

dfN = 2

dfD = 14

C ) The p value for the test can be obtained using Excel functon FDIST(F,dfN,dfD) as :

p value = FDIST(0.773059,2,14) = 0.480333

Since p value is greter than level of significance at 0.10 , We do not reject null hypothesis

At 10% level of significance there is sufficient evidence that the means are equal


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