Question

March 17-April 1	-2.05
March 18 - April 2	-2.0
March 19 - April 4	-2.02
March 20 - April 5	-2.03
March 22 - April 6	-1.77
March 24 - April 10	-1.41
March 25 - April 12	-1.6
March 27 - April 13	-1.38
March 28 - April 15	-1.38
March 30 - April 16	-1.16
Mean =	-1.68
Standard Deviation =	0.34

Do the following.

d) For each country test at 5% level if the mean for March is different from the mean for April using 10 paired samples.

Answer 1

using excel>addin>phstat>two sample test >paired t

we have

Paired t Test
Data
Hypothesized Mean Difference	0
Level of significance	0.05
Intermediate Calculations
Sample Size	10
DBar	-1.6800
Degrees of Freedom	9
SD	0.3359
Standard Error	0.1062
t Test Statistic	-15.8181
Two-Tail Test
Lower Critical Value	-2.2622
Upper Critical Value	2.2622
p-Value	0.0000
Reject the null hypothesis

since p value is less than 0.05 fo rgiven data so we can say that  the mean for March is different from the mean for April