In: Statistics and Probability
Random samples of employees in fast-food restaurants where the employer provides a training program were drawn. Of a sample of 67 employees who had not completed high school, 11 had participated in a training program provided by their current employer. Of an independent random sample of 113 employees who had completed high school but had not attended college, 27 had participated. Test at the 1% significance level the null hypothesis that the participation rates are the same for the two groups against the alternative that the rate is lower for those who have not completed high school.
Conduct the appropriate hypothesis test and report the p-value. Do not round intermediate calculations. Round your answer to four decimal places. Include the leading zero. Format: 0.0000
Hypothesis Test: Difference of two Proportions
Ho: p1 - p2 = 0
Ha: p1 - p2 < 0
sample #1 -----> not
completed
first sample
size,
n1= 67
number of successes, sample 1 =
x1= 11
proportion success of sample 1 , p̂1=
x1/n1= 0.1642
sample #2 -----> completed
second sample
size,
n2 = 113
number of successes, sample 2 = x2 =
27
proportion success of sample 1 , p̂ 2=
x2/n2 = 0.2389
difference in sample proportions, p̂1 - p̂2 =
0.1642 - 0.2389 =
-0.0748
pooled proportion , p = (x1+x2)/(n1+n2)=
0.2111
std error ,SE = =SQRT(p*(1-p)*(1/n1+
1/n2)= 0.0629
Z-statistic = (p̂1 - p̂2)/SE = ( -0.075
/ 0.0629 ) =
-1.1881
p-value =
0.1174
[Excel function =NORMSDIST(z)
decision : p-value>α,Don't reject null
hypothesis