Question

In: Statistics and Probability

A magazine company is planning to survey customers to determine the proportion who will renew their...

A magazine company is planning to survey customers to determine the proportion who will renew their subscription for the coming year. The magazine wants to estimate the population proportion with 95​% confidence and a margin of error equal to ±0.08.

What sample size is​ required?

The required sample size is customers. ​(Round up to the nearest whole number as​ needed.)

Solutions

Expert Solution

Solution :

Given that,

= 0.5

1 - = 1 - 0.5 = 0.5

margin of error = E = 0.08

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96 ( Using z table ( see the 0.025 value in standard normal (z) table corresponding z value is 1.96 )

Sample size = n = (Z/2 / E)2 * * (1 - )

= (1.96 / 0.08)2 * 0.5 * 0.5

= 150

Sample size = 150 rounded


Related Solutions

The proportion of customers who are completely satisfied in a recent satisfaction survey of 300 customers...
The proportion of customers who are completely satisfied in a recent satisfaction survey of 300 customers at XYC Inc. is found to be 0.26. (6 points) Test the hypothesis that the population proportion of customers who are completely satisfied is greater than 0.22 using the critical value approach and a 0.05 level of significance. Test the hypothesis that the population proportion of customers who are completely satisfied is less than 0.30 using the p-value approach and a 0.05 level of...
Suppose a marketing company wants to determine the current proportion of customers who click on ads...
Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.65. How many customers should the company survey in order to be 94% confident that the margin of error is 0.22 for the confidence interval of true proportion of customers who click on ads on their smartphones? Answer: (Round up your answer to nearest...
Suppose a marketing company wants to determine the current proportion of customers who click on ads...
Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.39 based on a random sample of 100 customers. Compute a 95% confidence interval for the true proportion of customers who click on ads on their smartphones and fill in the blanks appropriately. Answer: ___<P<____ (3 decimal Places)
The proportion of customers who do online shopping is believed to be 0.3. A survey of49...
The proportion of customers who do online shopping is believed to be 0.3. A survey of49 customers was taken. They were asked if they did online shopping. A. What is the probability of the sample proportion to be below 0.25? B. What is the probability that the sample mean is above 0.35? C. What is the role of the central limit theorem in solving this problem?
B. The proportion of customers who are completely satisfied in a recent satisfaction survey of 300...
B. The proportion of customers who are completely satisfied in a recent satisfaction survey of 300 customers at XYC Inc. is found to be 0.26. Test the hypothesis that the population proportion of customers who are completely satisfied is greater than 0.22 using the critical value approach and a 0.05 level of significance. e Test the hypothesis that the population proportion of customers who are completely satisfied is less than 0.30 using the p-value approach and a 0.05 level of...
A market research company conducted a telephone survey of 255 Melbourne households to determine the proportion...
A market research company conducted a telephone survey of 255 Melbourne households to determine the proportion of households seeking to purchase a new car in the next two years. An interval estimate of 0.151 to 0.289 was calculated. Determine the level of confidence (answer as percentage correct to two decimal places).
A market research company conducted a telephone survey of 320 Melbourne households to determine the proportion...
A market research company conducted a telephone survey of 320 Melbourne households to determine the proportion of households seeking to purchase a new car in the next two years. An interval estimate of 0.134 to 0.196 was calculated. Determine the level of confidence (answer as percentage correct to two decimal places).
1. Determine the sample size to survey the customers of a store in a mall, if...
1. Determine the sample size to survey the customers of a store in a mall, if there are 500 customers out of 11,000 that are in the stores of the corporation. Assume that the confidence level is 95% and the accepted margin of error is 0.05. 2. Determine the sample size from the previous exercise, assuming that the customer sample was taken from department stores where there are a total of 200 customers.
A regional hardware chain is interested in estimating the proportion of their customers who own their...
A regional hardware chain is interested in estimating the proportion of their customers who own their own homes. There is some evidence to suggest that the proportion might be around 0.70. Given this, what sample size is required if they wish a 90 percent confidence level with a margin of error of ± .025? About 355 Almost 1,300 Approximately 910 100
A survey was run by a high school student in order to determine what proportion of...
A survey was run by a high school student in order to determine what proportion of mortgage-holders in his town expect to own their house within 10 years. He surveyed 133 mortgage holders and found that the proportion of these that did expect to own their house within 10 years is 0.67. The student decides to construct a 95% confidence interval for the population proportion. a)Calculate the margin of error that the high school student will have. Give your answer...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT