In: Economics
A market research company conducted a telephone survey of 320 Melbourne households to determine the proportion of households seeking to purchase a new car in the next two years. An interval estimate of 0.134 to 0.196 was calculated. Determine the level of confidence (answer as percentage correct to two decimal places).
in the question sample size = 320
interval estimate is given as 0.134 - 0.196
interval estimate = point estimate +or - critical value * standard error
the difference between the intervals = 0.196 - 0.134
= 0.062
therefore critical value * standard error = 0.062/2
= 0.031
point estimate = 0.196 - 0.031
= 0.165
for population proportion standard error = square root of (P*Q/N) where P is the probability of success, Q =probability of failure and N= sample size
N = 320
Probability of success, P = 0.165 and
probability of failure, Q = 1 - P = 0.835
in this question std. error = square root of ( (0.165*0.835)/ 320)
= square root of (0.137775/320)
= 0.020749023
critical value*std. error = 0.031
therefore critical value = 0.031/ std. error
= 0.031/0.020749023
= 1.494
from the t table (statistical tables) the confidence value corresponding to the critical vale 1.494 is 0.9319.
therefore the level of confidence is 93.19%