A 20 ml aliquot of malonic acid solution was treated with 10.0 ml of 0.25M Ce4+...

A 20 ml aliquot of malonic acid solution was treated with 10.0 ml of 0.25M Ce4+ leading to the reaction CH2(COOH)2 + 6Ce4+ + 2H2O → HCOOH + 2CO2 + 6Ce3+ + 6H+ After standing for 10 minutes at 60°C, the solution was cooled and the x’ss Ce4+ was titrated with 0.1M Fe2+, requiring 14.4 ml to reach the ferroin end point. Calculate the M of the malonic in the sample.

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queen_honey_blossom answered 1 year ago

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