Question
In: Statistics and Probability
in a certain city, the monthly water bill amount is normally distributed with mean 25 and...
in a certain city, the monthly water bill amount is normally distributed with mean 25 and standard deviation 15. A sample of 36 bills was selected. What is the probability that the average water bill amount for the sample was between 26.7 and 30? round your answer to 4 decimal places. Do not write as percentage.
Solutions
Expert Solution
Solution :
Given that ,
mean = 
= 25
standard deviation = 
= 15
n = 36
= 25
= /
P(26.7< <30
) = P[(26.7 - 25) /2.5 < (
-
) / < (30 - 25) /2.5 )]
= P(0.68 < Z <2 )
= P(Z < 2) - P(Z < 0.68)
Using z table
=0.9772 - 0.7517
=0.2255
probability=0.2255
orchestra answered 2 years agoRelated Solutions
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