In: Statistics and Probability
The following is sample information. Test the hypothesis that the treatment means are equal. Use the 0.05 significance level.
| Treatment 1 | Treatment 2 | Treatment 3 |
| 3 | 4 | 8 |
| 6 | 3 | 10 |
| 3 | 8 | 6 |
| 10 | 7 | 8 |
Question: Complete the ANOVA table. (Round the SS, MS, and F values to 3 decimal places.)
| Source | SS | DF | MS | F |
| Treatment | ||||
| Error | ||||
| Total |
Please explain how you got your answers the best you can. I am trying to learn to do this myself. Thank you.
By using excel we can solve this question easily.
First, enter all data into excel.
Click on Data -------> Data Analysis--------> Anova:
Single-Factor-----> Input Data -------> Select all data
-------> Output Range : Select any empty cell -------->
ok
We get

| ANOVA | ||||||
| Source of Variation | SS | df | MS | F | P-value | F crit |
| Between Groups | 16.66667 | 2 | 8.333333 | 1.293103 | 0.32089 | 4.256495 |
| Within Groups | 58 | 9 | 6.444444 | |||
| Total | 74.66667 | 11 |
We have to test the hypothesis that the treatment means are equal. Use the 0.05 significance level.
The null and alternative hypothesis is

H1: At least one of the mean is different.
Test statistic F = 1.29
Critical value = 4.26
Test statistic < critical value we fail to reject null hypothesis.
Conclusion: The treatment means are equal.