In: Statistics and Probability
The following is sample information. Test the hypothesis that the treatment means are equal. Use the 0.01 significance level.
Treatment 1 | Treatment 2 | Treatment 3 |
9 | 9 | 3 |
8 | 10 | 5 |
4 | 10 | 4 |
9 | 7 | 4 |
a. State the null hypothesis and the alternate hypothesis.
H0: click to select (The treatment means are not all the same, the treatment means are the same) *pick which answer is correct from the options in the brackets*
H1: click to select (The treatment means are not all the same, the treatment means are the same) *pick which answer is correct from the options in the brackets*
b. What is the decision rule? (Round the final answer to 2 decimal places.)
Reject H0 if the test statistic is greater than _______ *fill in _______*
c. Compute SST, SSE, and SS total. (Round the final answers to 3 decimal places.)
SST = ________ *fill in ______*
SSE = ________ *fill in ______*
SS total = ________ *fill in ______*
d. Complete the ANOVA table. (Round the SS, MS, and F values to 3 decimal places.)
Source | SS | DF | MS | F |
Treatment | ______ | ______ | ______ | _____ |
Error | _______ | _______ | _____ | n / a |
Total | _______ | _____ | n / a | n / a |
*fill in _____, ignore N/A) |
e. State your decision regarding the null hypothesis.
click to select (Do not reject, reject )H0.*pick which answer is correct from the options in the brackets*
a.
Here we define the null and alternate hypothesis as follows:
H0: The treatment means are the same
H1: The treatment means are not all the same.
b.
We reject the null hypothesis if the test statistic is greater than F statistic with level of significance =0.01 and degrees of freedom 2,9
c.yij is the jth treatment corresponding to the ith level i=1,2,3 j=1,2,3,4
=52.670 where Ti0 is the treatment means corresponding to the ith treatment i=1,2,3
and CF is the correction factor = and
=77.670
and SSE= TSS-SST=25.00
d.
Source DF SS MS F-Value
treatments 2 52.67 26.333 9.48
Error 9 25.00 2.778
Total 11 77.67
Here MS= SS/DF
e.
here =8.0215
since F value >
we reject the null hypothesis at 99% level of significance.