In: Statistics and Probability
In what follows use any of the following tests/procedures: Regression, confidence intervals, one-sided t-test, or two-sided t-test. All the procedures should be done with 5% P-value or 95% confidence interval. Open Brain data. Claim: Male and female subjects have different total (brain) surface areas. 9. What test/procedure did you perform? a. One-sided t-test b. Regression c. Two-sided t-test d. Confidence interval 10. What is the P-value/margin of error? a. 0.450365624 b. 1.10877E-11 c. 0.435460528 d. 0.900731248 e. None of these 11. Statistical interpretation a. The 95% confidence interval does not contain the averages. b. Since P-value is too large we cannot conclude that the two variables have different averages. c. Since P-value is too large we cannot claim that there is connection between two variables. d. Since P-value is small we can claim that there is connection between two variables. e. None of these 12. Conclusion a. Yes, I am confident that the averages are different. b. No, I cannot claim that the average are different.
To test the claim Male and female subjects have different total (brain) surface areas,
9)
Correct Answer: c. Two-sided t-test
Explanation:
Since we are comparing two sample's (Male and female ) total (brain) surface areas 2 sample t statistic will be used to test whether the population means of total (brain) surface areas are equal for both Male and female
10)
Correct Answer: e. None of these
Explanation:
The P-value for two sided t test is obtained as follow,
From the data values, the mean and average for both the samples are,
Male | Female | |
1806.31 | 1913.88 | |
2018.92 | 1902.36 | |
2154.67 | 2264.25 | |
1767.56 | 1866.99 | |
971.63 | 1743.04 | |
1689.6 | 1684.89 | |
2136.37 | 1860.24 | |
1966.81 | 2216.4 | |
1827.92 | 1850.64 | |
1773.83 | 1709.3 | |
mean | 1811.362 | 1901.199 |
sd | 335.7145 | 195.8892 |
n | 10 | 10 |
The test statistic is obtained using the formula,
Since n_1 = n_2 = n = 10, the formula reduced to,
Now, the P-value is obtained from t distribution table for degree of freedom = n_1+n_2-2 = 18.
11)
Correct Answer: b. Since P-value is too large we cannot conclude that the two variables have different averages
Explanation:
The P-value = 0.4742 is greater than 0.05 at 5% significance level, we cannot conclude that there is different in averages.
12)
Correct Answer: a. Yes, I am confident that the averages are different.
Explanation:
Since there is sufficient statistical evidence we cannot reject the null hypothesis.