In: Statistics and Probability
A random sample of n =100 is selected from a normal population with mean μ = 24 and standard deviation σ = 1.25.
Find the probability that is less than 24.3
Solution :
Given that,
mean = = 24
standard deviation = = 1.25
n = 100
= 24
= / n = 1.25/ 100=0.125
P( <24.3 ) = P[( - ) / < (24.3 - 24) /0.125 ]
= P(z <2.4 )
Using z table
= 0.9918
probability= 0.9918