In: Statistics and Probability
A random sample of n =100 is selected from a normal population with mean μ = 24 and standard deviation σ = 1.25.
Find the probability that is less than 24.3
Solution :
Given that,
mean =
= 24
standard deviation =
= 1.25
n = 100
= 24
=
/
n = 1.25/
100=0.125
P(
<24.3 ) = P[(
-
) /
< (24.3 - 24) /0.125 ]
= P(z <2.4 )
Using z table
= 0.9918
probability= 0.9918