In: Statistics and Probability
A random sample of n = 100 scores is selected from a normal population with a mean of μ = 60 and a standard deviation of σ = 20. What is the probability of obtaining a sample mean greater than M = 57?
Solution :
Given that,
mean =
= 60
standard deviation =
= 20
n=100
=
=60
=
/
n = 20 /
100 = 2
P( >57) = 1 - P(
<57 )
= 1 - P[(
-
) /
< (57-60) /2 ]
= 1 - P(z < -1.5)
Using z table
= 1 - 0.0668
= 0.9332
probability=0.9332