In: Statistics and Probability
Since an instant replay system for tennis was introduced at a major tournament, men challenged 14301430 referee calls, with the result that 416416 of the calls were overturned. Women challenged 740740 referee calls, and 219219 of the calls were overturned. Use a 0.050.05 significance level to test the claim that men and women have equal success in challenging calls. Complete parts (a) through (c) below.
For men, we have that the sample size is N1=1430, the number of favorable cases is X1=416, so then the sample proportion is
For women, we have that the sample size is N2=740, the number of favorable cases is X2=219, so then the sample proportion is
The value of the pooled proportion is computed as
Also, the given significance level is α=0.05.
(1) Null and Alternative Hypotheses
The following null and alternative hypotheses need to be tested:
Ho : p1=p2
Ha : p1̸ p2
This corresponds to a two-tailed test, for which a z-test for two population proportions needs to be conducted.
(2) Rejection Region
The significance level is α=0.05, and the critical value for a two-tailed test is zc=1.96.
The rejection region for this two-tailed test is R = { z : ∣z∣ > 1.96 }
(3) Test Statistics
The z-statistic is computed as follows:
(4) Decision about the null hypothesis
Since it is observed that ∣z∣ = 0.244 ≤ zc = 1.96, it is then concluded that the null hypothesis is not rejected.
Using the P-value approach: The p-value is p=0.8069, and since p = 0.8069 ≥ 0.05, it is concluded that the null hypothesis is not rejected.
(5) Conclusion
It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the population proportion p1 is different than p2, at the 0.05 significance level.
Hence we can conclude that men and women have equal success in challenging calls.