In: Statistics and Probability
Let us summarize what is given in the problem. From the statements, we form a 2X2 contingency table as below:
Field | Lab | Total | |
Male | 176 | 107 | 283 |
Female | 60 | 115 | 175 |
Total | 236 | 222 | 458 |
From this data we need to assess
Gero argued that this pattern in archaeology reflected broader expectations that the public sphere was gendered male while the domestic sphere was gendered female. Is the pattern in Gero’s data statistically significant?
That is we need to assess whether the gender and the homing(Women at home) are associated.
Null Hypothesis:
The two factors gender and Homing are not associated or are independent
Alternative Hypothesis:
There is an association between two factors.
Test statistics:
We shall use the
Where is the Observed Frequency and is the observed frequency and
Where R is the row total of the cell and C is the column total for the cell, and T is the overall total.
For example in the above table, the for 176(Male field is) 283*236/458=145.825. We need to calculate for all the 4 entries and then calculate the Test statistic.
Expected Values
Field | Lab | Total | |
Male | 145.8253 | 137.1747 | 283 |
Female | 90.1747 | 84.8253 | 175 |
Total | 236 | 222 | 458 |
We then calculate the statistics as
The tabulated value for at (2-1)x(2-1) =1 df is 3.841 at 5% level of significance.
Since the calculated value is more than the tabulated value, the null hypothesis is rejected and hence we conclude that there is an association between the gender and the home.
Strength Test:
We shall use a Phi coefficient:
where a,b,c and d are the cell counts.
The interpretation is the same as the correlation coefficient. Here, it is 0.2713 which indicates a little or no association between these two factors.