In: Statistics and Probability
Below are the values for two variables x and y obtained from a sample of size 5. We want to build a regression equation based the sample data.
ŷ = b₀ + b₁x |
y | x |
16 | 5 |
21 | 10 |
8 | 6 |
28 | 12 |
53 | 14 |
11 |
On average the observed y deviate from the predicted y by, |
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a |
10.73 |
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b |
10.04 |
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c |
9.53 |
||||
d |
8.76 |
12 |
Sum of squares total (SST) is, |
||
a |
1096.3 |
||
b |
1178.8 |
||
c |
1296.7 |
||
d |
1361.5 |
13 |
Sum of squares regression (SSR) is, |
||
a |
906.06 |
||
b |
983.56 |
||
c |
1008.47 |
||
d |
1065.20 |
14 |
The fraction of variations in y explained by x is: |
|||
a |
0.5534 |
|||
b |
0.6149 |
|||
c |
0.7686 |
|||
d |
0.8455 |
15 |
The x and y data are sample data from the population of X and Y to compute b₁ as an estimate of the population slope parameter β₁. The sample statistic b₁ is the estimator of the population parameter β₁. The estimated measure of dispersion of the sample statistic b₁ is, |
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a |
0.929 |
|||||||
b |
1.239 |
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c |
1.549 |
|||||||
d |
1.936 |
16 |
The margin of error for a 95% confidence interval for β₁ is, |
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a |
4.77 |
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b |
4.34 |
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c |
3.94 |
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d |
2.96 |
17 |
To perform a hypothesis test with the null hypothesis H₀: β₁ = 0, we need a test statistic. The test statistic for this hypothesis test is, |
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a |
1.741 |
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b |
2.123 |
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c |
2.589 |
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d |
3.157 |
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Answer:
11)
9.53
12)
1178.8
13)
906.06
14)
0.7686 |
15)
1.239
16)
confidence interval for slope
α= 0.05
t critical value= t α/2 =
3.182 [excel function: =t.inv.2t(α/2,df) ]
estimated std error of slope = Se/√Sxx =
9.53491 /√ 59.20 =
1.239
margin of error ,E= t*std error = 3.182 * 1.239 = 3.94
17)
t stat = estimated slope/std error =ß1 /Se(ß1) = 3.9122 / 1.2392 = 3.157