Question

(java) Show what the following program would print. Be sure to show work space. (Hint: Watch out for integer division) SHOW WORK

public class Q2{

public static void main(String[] args){

int a = 1, b = 4, c = 5;

double x = 3.0;

a = method (b,x);

System.out.println( "first: " + a + " " + b + " " + c);

a = 12;

b = 5;

c = method(a - b, 10.0) * 2;

System.out.println( "then: " + c);

}

public static int method (int t, double v){

int w;

if (v > 5.0)

w = t / 3 + 4;

else

w = 25;

System.out.println( "in method: " + w);

return 2 * w;

}

}

Answer 1

Output:-

in method: 25

first: 50 4 5

in method: 6

then: 24

Output Screenshot:-

Explanation:-

First it will go to main class and there the variables with values are

a = 1

b = 4

c = 5

x = 3.0 (it is double)

The next statement is a = method(b,x)

The it will calls the method function with values b and x those are 4 and 3.0

In method the variables are t and v, then t = 4 and v = 3.0 and a variable w with integer type.

In if condition v > 5.0 ---> Here v value we have 3.0 so the condition is false.

Then it will go to else condition

In else condition w is declared as 25 and next prints in method: w value

which is in method: 25

Then it will return 2*w

That is 50.

We called the function a = method(b,x)

Then the 50 value is returned to a. So a = 50

Now in main mehotd the a = method(b,x) is over.

Next statement it prints first: a b c

Which means we get a is 50 and b is 4 and c is 5 as declared. So the output is first: 50 4 5

Then next we declared a = 12 and b = 5

and for c we called the method function as c = method(a-b,10.0)*2

Here a is 12 and b is 5. After calling the method function the method function has variables t and v. In the method the variables are a-b and 10.0

So t is a-b and v is 10.0

Then the values are t is 12-5 which is 7 and v is 10.0

w is in declared variable in method function as before.

In if condition v>5.0 ---> which means 10.0>5.0

The condition is true the w is t/4+4

Which is 7/3+4 and by simpifying we will get 6

Then it prints in method: w value

Which is in method: 6

and returns 2*w for the method. Which means it returns 2*6 that is 12. It will return the value 12 for c. Because we called the method for the value c which is c=method(a-b,10.0)

In main function we get method(a-b,10.0) is 12 and in the statement it has *2 so the c value is 24

Next it will prints then: c value

Which is then: 24

Please UPVOTE thank you...!!!