In: Statistics and Probability
IQ tests are designed to yield results that are approximately Normally distributed. Researchers think believe that the standard deviation, σ, is 15. A reporter is interested in estimating the average IQ of employees in a large high-tech firm in California. She gathers the IQ information on 22 employees of this firm and recoreds the sample mean IQ as 106. Let X represent a random variable describing a person's IQ: X~N(µ, 15).
a. Find the standard error of the sample mean.
b. Calculate a 90% confidence interval.
c. Interpret the confidence interval in the context of the problem.
( Need excel form )
Solution :
Given that,
Point estimate = sample mean =
= 106
Population standard deviation =
= 15
Sample size = n = 22
a) = / n = 15 / 22 = 3.20
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645
Margin of error = E = Z/2
*
= 1.645 * 3.20
= 5.26
b) At 90% confidence interval estimate of the population mean
is,
± E
106 ± 5.26
( 100.74, 111.26 )
c) We are 90% confident that the true mean of employees in a large high-tech firm in California between 100.74 and 111.26