In: Statistics and Probability
The heights of female students in a university are approx normally distributed with a mean of 162 cm and a standard dev of 8 cm. Explain your answers.
a) Approx 68% of all female students in a university will have heights between ____ cm and ____ cm.
b) Heights greater than ____ cm would be considered peculiar.
Given that,
mean = = 162
standard deviation = = 8
middle 68% of score is
P(-z < Z < z) = 0.68
P(Z < z) - P(Z < -z) = 0.68
2 P(Z < z) - 1 = 0.68
2 P(Z < z) = 1 + 0.68 = 1.68
P(Z < z) = 1.68 / 2 = 0.84
P(Z < 0.99) = 0.84
z ±0.99
z = - 0.99
Using z-score formula
x= z * +
x= - 0.99 *8+162
x=154.08
z = 0.99
Using z-score formula
x= z * +
x= 0.99*6+162
x= 167.94
Approx 68% of all female students in a university will have heights between 154.08 cm and 167.94