Question

Question 15

According to a union agreement, the mean income for all senior-level workers in a large service company equals $500 per week. A representative of a women's group decides to analyze whether the mean income for female employees matches this norm. The data for a random sample of 9 female employees are given below:

337, 412, 508, 455, 481, 523, 396, 368, 408

Test, at significance level 0.05, that the mean income for all female employees in this company is not different from $500.

The test is a

Question 15 options:

	One-sample t test
	one-sample z test
	two-sample t test
	two-sample z test

Question 16

According to a union agreement, the mean income for all senior-level workers in a large service company equals $500 per week. A representative of a women's group decides to analyze whether the mean income for female employees matches this norm. The data for a random sample of 9 female employees are given below:

337, 412, 508, 455, 481, 523, 396, 368, 408

Test, at significance level 0.05, that the mean income for all female employees in this company is not different from $500.

The value of the test statistic is

Question 16 options:

	3.2065
	2.8134
	-3.2065
	-2.8134

Question 17

According to a union agreement, the mean income for all senior-level workers in a large service company equals $500 per week. A representative of a women's group decides to analyze whether the mean income for female employees matches this norm. The data for a random sample of 9 female employees are given below:

337, 412, 508, 455, 481, 523, 396, 368, 408

Test, at significance level 0.05, that the mean income for all female employees in this company is not different from $500.

The p-value is

Question 17 options:

	0.0125
	0.0250
	0.9875
	0.0062

Question 18

According to a union agreement, the mean income for all senior-level workers in a large service company equals $500 per week. A representative of a women's group decides to analyze whether the mean income for female employees matches this norm. The data for a random sample of 9 female employees are given below:

337, 412, 508, 455, 481, 523, 396, 368, 408

Test, at significance level 0.05, that the mean income for all female employees in this company is not different from $500.

We conclude that

Question 18 options:

	the data provide sufficient evidence that the mean income for all female employees in this company is not different from $500.
	the data provide sufficient evidence that the mean income for all female employees in this company is different from $500.
	the data do not provide sufficient evidence that the mean income for all female employees in this company is not different from $500.
	the data do not provide sufficient evidence that the mean income for all female employees in this company is different from $500.

Question 19

Two different methods for determining chlorine were used on samples of Cl$_2$-demand-free water for various doses and contact times. Observations shown below are in mg/L. Here are the data:

Subject Method.I Method.II
1     0.39      0.36  
2     0.84      1.35
3     1.76      2.56
4     3.35      3.92
5     4.69      5.35
6     7.70      8.33
7    10.52     10.70
8    10.92     10.91

Test, at significance level 0.05, that there is a difference between the two methods.

The test is a

Question 19 options:

	two-sample t test
	paired t test
	two-sample z test
	None of these

Question 20

Two different methods for determining chlorine were used on samples of Cl$_2$-demand-free water for various doses and contact times. Observations shown below are in mg/L. Here are the data:

Subject Method.I Method.II
1     0.39      0.36  
2     0.84      1.35
3     1.76      2.56
4     3.35      3.92
5     4.69      5.35
6     7.70      8.33
7    10.52     10.70
8    10.92     10.91

Test, at significance level 0.05, that there is a difference between the two methods.

The p-value of the test is

Question 20 options:

	0.8457
	0.0034
	0.6626
	0.008

Answer 1

Mean=432, SD=63.62, n=9

15)We need to conduct a 1 sample t test

17)pvalue=2*P(t<-3.2065,8dof)=0.0125

18)As value<0.05, we need to reject H0 and hence Ans-> "the data provide sufficient evidence that the mean income for all female employees in this company is different from $500."

19) as we are comparing groups and sample size<30, we need to conduct 2 sample t test

20)For this analysis, we need to take the difference between the two groups and find the mean and standard deviation. We need to find if the mean deviates from 0 or not

Mean=-0.41375, SD=0.32,n=8

pvalue=2*P(t<-3.6454,7dof)=0.0083