A marine biologist claims that the mean length of mature female pink seaperch is different in...

A marine biologist claims that the mean length of mature female pink seaperch is different in fall and winter. A sample of 6 mature female pink seaperch collected in fall has a mean length of 106 millimeters and a standard deviation of 14 millimeters. A sample of 8 mature female pink seaperch collected in winter has a mean length of 101 millimeters and a standard deviation of 13 millimeters. At alphaequals 0.20, can you support the marine biologist's claim? Assume the population variances are equal. Assume the samples are random and independent, and the populations are normally distributed.

Standardized test statistic

t = ??

Expert Solution

orchestra answered 1 year ago

A marine biologist claims that the mean length of male harbor seals is greater than the...

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It is known that white sharks grow to a mean length of 18.9 feet. A marine...

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A - Suppose Wesley is a marine biologist who is interested in the relationship between the...

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A biologist is conducting experiments with scientific cross pollination of pink roses with white, red, and...

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QUESTION: Marine biologist counted the number of tentacles and noted the color of jellyfish in a...

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A biologist measures the lengths of a random sample 45 mature brown trout in a large...

A biologist measures the lengths of a random sample 45 mature brown trout in a large lake and finds that the sample a mean weight of 41 pounds. Assume the population standard deviation is 3.7 pounds. Based on this, construct a 99% confidence interval for the mean weight of all mature brown trout in the lake. Round your anwers to two decimal places. < μ

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