In: Chemistry
Estimate the volume of spent fuel generated annually by a 1 GW if the fuel is UO2 enriched to 3.0% 235 and the density of the fuel is 3000 kg/m3.
0.03 kg of U235 per kg of loaded uranium will undergo fission, producing something like the
(183.6 MeV * 1.6022 *10-19 MJ ) / 235.04 amu / 0.03 Kg = 4.171*106 MJ/Kg
Thus, on the basis of uranium loaded, the fission produces (0.03)( 4.17x106) = 1.25x106 MJ/kg.
A 1000 MWe power plant, operating at an efficiency of 33% requires a heat input of (1000 MW)/33% = 3000 MW = 3000 MJ/s. If the plant operates at a 95% capacity factor, the total heat energy input during the year will be (95%)(3000 MJ/s)(3600 s/h)(24 h/day)(365 d/yr) = 9.08x1010 MJ. The mass of uranium required then is (9.08x1010 MJ/yr) / (1.25x106 MJ/kg) = 5.47x104 kg/yr of uranium. The amount of UO2 is found by multiplying by the molar mass ratio of UO2 to U which is (238 + 32)/238 = 1.143.
Thus the required amount of UO2 is (1.143)(5.47x104 kg/yr) = 6.21x104 kg/yr of UO2.