Suppose that 32% of people have a dog, 27% of people have a cat, and 12%...

Suppose that 32% of people have a dog, 27% of people have a cat, and 12% have both. What is the probability that someone owns a dog but not a cat?

Expert Solution

P(dog) = 0.32

P(cat) = 0.27

P(dog and cat) = 0.12

P(dog but not a cat) = P(dog) - P(dog and cat) = 0.32 - 0.12 = 0.2

orchestra answered 1 year ago

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