In: Statistics and Probability
Suppose that 32 of the 1500 people that received an email we sent, clicked on the offer image. What is the estimate for the left end point of a 95% confidence interval for the proportion of people in the population that will click on an offer that we send them?
We have given,
x=32
n=1500
Estimate for sample proportion=0.0213
Level of significance is =1-0.95=0.05
Z critical value(using Z table)=1.96
Confidence interval formula is
=(0.0140,0.0286)
Lower limit for confidence interval=0.0140
Upper limit for confidence interval=0.0286
Therefore, the estimate for the left end point of a 95% confidence interval =0.0140 |