Question

In: Statistics and Probability

A data set is given a) (a) Draw a scatter diagram. Comment on the type of...

A data set is given

a)

(a) Draw a scatter diagram. Comment on the type of relation that appears to exist between x and y.

​(b) Given that

x overbarxequals=3.83333.8333​,

s Subscript xsxequals=2.40142.4014​,

y overbaryequals=3.98333.9833​,

s Subscript ysyequals=1.74521.7452​,

and

requals=negative 0.9457−0.9457​,

determine the​ least-squares regression line.

​(c) Graph the​ least-squares regression line on the scatter diagram drawn in part​ (a).

x 0 2 4 5 6 6
y 6.0 5.8 4.7 3.0 2.1 2.3

Solutions

Expert Solution

(a) SCATTER DIAGRAM

Line of Regression Y on X i.e Y = bo + b1 X
X Y (Xi - Mean)^2 (Yi - Mean)^2 (Xi-Mean)*(Yi-Mean)
0 6 14.694 4.067 -7.731
2 5.8 3.361 3.3 -3.331
4 4.7 0.028 0.514 0.119
5 3 1.361 0.967 -1.147
6 2.1 4.695 3.547 -4.081
6 2.3 4.695 2.833 -3.647

calculation procedure for regression
mean of X = sum ( X / n ) = 3.8333
mean of Y = sum ( Y / n ) = 3.9833
sum ( (Xi - Mean)^2 ) = 28.834
sum ( (Yi - Mean)^2 ) = 15.23
sum ( (Xi-Mean)*(Yi-Mean) ) = -19.818
b1 = sum ( (Xi-Mean)*(Yi-Mean) ) / sum ( (Xi - Mean)^2 )
= -19.818 / 28.834
= -0.687
bo = sum ( Y / n ) - b1 * sum ( X / n )
bo = 3.9833 - -0.687*3.8333 = 6.618
value of regression equation is, Y = bo + b1 X
least-squares regression line = Y'=6.618-0.687* X          

(c) Regression line on the graph


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