Question

I am stumped on these problems and homework question, please could I get the answers to the questions below from an expert. Thank you

5). Suppose that two population proportions are being compared to test weather there is any difference between them. Assume that the test statistic has been calculated to be z= 2.21. Find the p-value for this situation?   a). p-value = 0.4864 b). p-value = 0.0272 c). p-value = 0.9728 d). p-value = 0.0136.

8). If you are given the following results of a paired-difference test. = -4.6 sd = 0.25 n = 16 Construct a 99 percent confidence interval estimate for the paired difference in mean values?   a) - 3.141___-2.812 b) -5.241____-4.971 c). -4.784___-4.416 d). -2.912____-2.718

16). Given a population in which the probability of success is p= 0.20, if a sample of 500 items is taken, than calculate the probability the proportion of successes in the sample will be between 0.18 and 0.23 if the sample size is 200?    a). 0.8712 b). 0.8911 c). 0.7121 d). 0.6165

17). Construct a 98% confidence interval estimate for the population mean given the following values?    a). (117.46, 122.54) b). (113.67, 126.33) c). (113.41, 126.59) d). (113.13, 126.87).

23). If a distribution for a quantitative variable is thought to be nearly symmetric with very little variation, and a box and whisker plot is created for this distribution, which of the following is true? a). The box will be quite wide but the whisker will be very short b). The upper whisker will be much longer than the lower whisker. c). The whiskers should be about half as long as the box is wide d). The left and right-hand edges of the box will be approximately equal distance from the median.

24). A randomly selected customer support wait time (from a normal distribution) is calculated to be 1.8 standard deviations above its mean. What is the probability that another randomly selected customer wait time from the distribution will be less than 1.8 standard deviations from the mean? a). 0.9641 b).0.9976 c). 0.9281 d). 0.0359

25). The advantage of using the interquartile range versus the range as a measure of variation is?   a). it is easier to compute b). it gives a value that is closer to the true variation. c). it is less affected by extremes in the data d). it utilizes all the data in its computation.

34). Given a population where the proportion of items with a desired attribute is p=0,25, if a sample of 400 is taken, what is the probability the proportion of successes in the sample will be greater than 0.22? a). 0.9162 b). 0.8412 c). 0.8812 d). 0.7141

Answer 1