Given a random sample of size 16 from a normally distributed population with a mean of...

Given a random sample of size 16 from a normally distributed population with a mean of 100 and standard deviation of 24, find P(x bar≤90)

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Expert Solution

Solution :

Given that,

mean = = 100

standard deviation = = 24

n = 16

= 100

= / $\sqrt$ n = 24 $\sqrt$ 16 = 6

p ( 90 )

P ( - /) ( 90 - 100 / 6)

P( z - 10 / 6 )

P ( z -1.67 )

Using z table

= 0.0475

Probability = 0.0475

orchestra answered 11 months ago

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