In: Statistics and Probability
Given a random sample of size 16 from a normally distributed population with a mean of 100 and standard deviation of 24, find P(x bar≤90)
Solution :
Given that,
mean =
= 100
standard deviation =
= 24
n = 16
= 100
=
/
n = 24
16 = 6
p (
90
)
P ( -
/
)
( 90 - 100 / 6)
P( z
- 10 / 6 )
P ( z
-1.67 )
Using z table
= 0.0475
Probability = 0.0475