In: Statistics and Probability
Given a random sample of size 16 from a normally distributed population with a mean of 100 and standard deviation of 24, find P(x bar≤90)
Solution :
Given that,
mean = = 100
standard deviation = = 24
n = 16
= 100
= / n = 24 16 = 6
p ( 90 )
P ( - /) ( 90 - 100 / 6)
P( z - 10 / 6 )
P ( z -1.67 )
Using z table
= 0.0475
Probability = 0.0475