Suppose the local Best Buy store averages 301 customers every day entering the facility with a...

Suppose the local Best Buy store averages 301 customers every day entering the facility with a standard deviation of 80 customers. A random sample of 50 business days was selected. What is the probability that the average number of customers in the sample is between 290 and 310?

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Expert Solution

Solution :

Given that,

mean = = 301

standard deviation = = 80

n = 50

= = 301

= / n = 80/ 50 = 11.3137

P(290 < < 310) = P((290 - 301) / 44.3137<( - ) / < (310 - 301) / 11.3137))

= P(-0.97 < Z < 0.80)

= P(Z < 0.80) - P(Z < -0.97) Using standard normal table,

= 0.7881 - 0.1660

= 0.6221

Probability = 0.6221

The probability that the average number of customers in the sample is between 290 and 310 is 0.6221.

orchestra answered 1 year ago

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