In: Statistics and Probability
Consider two samples: one which has 3 observations with a mean of 8.3 and a standard deviation of 1.2, and another which has 10 observations with a mean of 3.0 and a standard deviation of 5.4. Based on these samples, what is likely to be true for the populations if we test at the 5% level?
For testing of mean,
Null hypothesis (Ho) :
Alternative hypothesis (H1) :
Test statistic is given by -
Where,
.
m1= first sample mean = 8.3
m2 = second sample mean = 3
n1= sample size of first sample = 3
n2= sample size of second sample = 10
s1= standard deviation of first sample = 1.2
s2 = standard deviation of second sample = 5.4
So, s =√(263.88/10) = 5.137
Therefore,
= 1.568
Critical value of t at 0.05 level of significance and 10 degrees of freedom is 2.228 (This can be obtained from t table)
Since, t calculated < t critical, hence, we may not reject the null hypothesis. Hence, the two means are equal.
For testing of Variance,
Null hypothesis:
Alternative facts:
Test statistic is given by-
f = larger sample variance/ smaller sample variance
=
=
= 20.25
Critical value of f at 9 and 2 degrees of freedom at 5% Level of significance is 19.38 as obtained from the f table.
Since, f calculated > f critical, we may reject the null hypothesis. So, variances are not equal.
So,the correct the option is (b) only equal means.