In: Statistics and Probability
An unknown distribution has a mean of 50 and a standard deviation of ten samples of size n=30 are drawn randomly from population. Find the probability that the sample mean is between 45 and 55.
Solution :
Given that ,
mean = = 50
standard deviation = = 10
n = 30
= = 50
= / n = 10 / 30
P(45 < < 55 )
= P[(45 - 50) / 10 / 30 < ( - ) / < (55 - 50) / 10 / 30 )]
= P( -2.74 < Z < 2.74 )
= P(Z < 2.74 ) - P(Z < -2.74)
Using z table,
= 0.9969 - 0.0031
= 0.9938