In: Statistics and Probability
Let x = boiler steam pressure in 100 lb/ in2 and let y = critical sheer strength of boiler plate steel joints in tons/ in2. We have the following data for a series of factory boilers.
x | 4 | 5 | 6 | 8 | 10 |
y | 3.4 | 4.2 | 6.3 | 10.9 | 13.3 |
(b) Use the (x', y') data points and a calculator with
regression keys to find the least-squares equation y' = a +
bx'. What is the correlation coefficient? (Use 3 decimal
places.)
y' | = | + x' |
r | = |
(c) Use the results of part (b) to find estimates for α and β in
the power law y =
αxβ. Write the power equation
for the relationship between steam pressure and sheer strength of
boiler plate steel. (Use 3 decimal places.)
α | = | |
β | = | |
= | · x^ |
(b) Using Excel we have found equation of regression line:
SUMMARY OUTPUT | |
Regression Statistics | |
Multiple R | 0.990672 |
R Square | 0.981431 |
Adjusted R Square | 0.975241 |
Standard Error | 0.040266 |
Observations | 5 |
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | |
Intercept | -0.45119 | 0.102786 | -4.38959 | 0.021902 | -0.7783 | -0.12408 | -0.7783 | -0.12408 |
log(X) | 1.599913 | 0.127058 | 12.59195 | 0.00108 | 1.195556 | 2.004269 | 1.195556 | 2.004269 |
herefore, we find that the regression equation is:
log(Y) = -0.451 + 1.600*log(X)
i.e. Y'=-0.451 + 1.600 *X'
from above table we can find correlation coefficient.
Multiple R. This is the correlation coefficient. It tells you how strong the linear relationship
Hence correlation coefficient is 0.991.
(c) Use the results of part (b) to find estimates for ?and ? in the power law y = ?x?. Write the power equation for the relationship between steam pressure and sheer strength of boiler plate steel. (Use 3 decimal places.)
function value
mean of x= 0.783
mean of y =0.790
correlation coefficient r= 0.991
? =1.161
? =1.580
?=1.161*x1.580
NOTE:If you satisfy with this solution please give me a thumb up. Thank-you :)