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In: Chemistry

A certain weak acid, HA, has a Ka value of 2.8×10−7. Calculate the percent ionization of...

A certain weak acid, HA, has a Ka value of 2.8×10−7. Calculate the percent ionization of HA in a 0.10 M solution. Calculate the percent ionization of HA in a 0.010 M solution.

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Expert Solution

Let a be the dissociation of the weak acid
                            HA <---> H + + A-

initial conc.            c               0         0

Equb. conc.         c(1-a)          ca       ca

Dissociation constant , Ka = ca x ca / ( c(1-a)

                                         = c a2 / (1-a)

In the case of weak acids α is very small so 1-a is taken as 1

So Ka = ca2

==> a = √ ( Ka / c )

Given Ka = 2.8x10-7

          c = concentration = 0.10 M

Plug the values we get a = 1.673x10-3

∴ % ionization =  1.673x10-3 x 100 =  1.673x10-1

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Calculation of percentage of ionization in 0.010 M solution :

a = √ ( Ka / c )

Given Ka = 2.8x10-7

          c = concentration = 0.010 M

Plug the values we get a = 5.29x10-3

∴ % ionization = 5.29x10-3 x 100 = 0.529


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